The power in an $AC$ circuit is given by $P = E_{rms}I_{rms} \cos \phi$. The value of $\cos \phi$ in a series $LCR$ circuit at resonance is:

$A$ $10 \Omega$ resistance,$5 \ mH$ coil,and $10 \ \mu F$ capacitor are joined in series. When an alternating current source of suitable frequency is joined to this combination,the circuit resonates. If the resistance is halved,the resonant frequency is

What is the sharpness of resonance and obtain an equation for the $Q$ factor?

The power factor in an $L-C-R$ circuit at resonance is

In a series $LCR$ circuit,at resonance,the peak value of current will be [where $E_0$ is peak emf,$R$ is resistance,$\omega L$ is inductive reactance,and $1/\omega C$ is capacitive reactance].

An $LCR$ series circuit is connected to an external $emf$,$e = 200 \sin(100 \pi t) \ V$. The values of capacitance and resistance in the circuit are $1 \ \mu F$ and $100 \ \Omega$ respectively. The amplitude of current in the circuit is maximum when the inductance is (in henry):