The power of a pump,which can pump 500 ,kg of | vedclass

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(C) The power $P$ is defined as the rate of doing work,given by $P = \frac{W}{t}$.Here,the work done $W$ is equal to the potential energy gained by th

Vedclass · Accepted Answer

$50$

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(C) The power $P$ is defined as the rate of doing work,given by $P = \frac{W}{t}$.Here,the work done $W$ is equal to the potential energy gained by the water,$W = mgh$.Given:Mass $m = 500 \,kg$Height $h = 100 \,m$Time $t = 10 \,s$Acceleration due to gravity $g = 10 \,m/s^2$Substituting the values:$W = 500 	imes 10 	imes 100 = 500,000 \,J$$P = \frac{500,000 \,J}{10 \,s} = 50,000 \,W$Since $1 \,kW = 1,000 \,W$,we have:$P = \frac{50,000}{1,000} \,kW = 50 \,kW$.Therefore,the correct option is $C$.

The power of a pump,which can pump $500 \,kg$ of water to a height of $100 \,m$ in $10 \,s$,is .......... $kW$. (Take $g = 10 \,m/s^2$)

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