The pressure exerted by an ideal gas on the w | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The pressure $P$ exerted by an ideal gas is given by the kinetic theory of gases as $P = \frac{1}{3} \rho v_{rms}^2$,where $\rho$ is the density a

Vedclass · Accepted Answer

$2/3$ of the kinetic energy per unit volume of a gas

Vedclass · Answer

(B) The pressure $P$ exerted by an ideal gas is given by the kinetic theory of gases as $P = \frac{1}{3} \rho v_{rms}^2$,where $\rho$ is the density and $v_{rms}$ is the root mean square velocity.We know that the kinetic energy per unit volume $(u)$ is given by $u = \frac{1}{2} \rho v_{rms}^2$.Therefore,$\rho v_{rms}^2 = 2u$.Substituting this into the pressure equation: $P = \frac{1}{3} (2u) = \frac{2}{3} u$.Thus,the pressure exerted by an ideal gas is $2/3$ of the kinetic energy per unit volume of the gas.

The pressure exerted by an ideal gas on the walls of a container is

Similar Questions

The translational kinetic energy of gas molecules for one mole of the gas is equal to

The temperature of a gas is $-68^\circ C$. At what temperature in $^\circ C$ will the average kinetic energy of its molecules be twice that of at $-68^\circ C$?

Write the equation of pressure of an ideal gas in terms of its density.

Explain the kinetic interpretation of temperature.

The average molecular kinetic energy of a gas over a long time interval is...

Vedclass Test Series

Exam Paper Generator

Online Exam Module