The pressure of a gas is 100 kPa. If it is c | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Given,pressure $p = 100 \ kPa = 10^{5} \ Pa$. Initial volume $V_{1} = 1 \ m^{3}$. Final volume $V_{2} = 10 \ dm^{3} = 10 	imes 10^{-3} \ m^{3} =

Vedclass · Accepted Answer

$99000$

Vedclass · Answer

(D) Given,pressure $p = 100 \ kPa = 10^{5} \ Pa$. Initial volume $V_{1} = 1 \ m^{3}$. Final volume $V_{2} = 10 \ dm^{3} = 10 	imes 10^{-3} \ m^{3} = 0.01 \ m^{3}$. Work done on the system is given by $W = -p_{ext} \Delta V$. Since the gas is compressed,work is done on the system,so $W = p_{ext}(V_{1} - V_{2})$. $W = 10^{5} \ Pa 	imes (1 \ m^{3} - 0.01 \ m^{3}) = 10^{5} 	imes 0.99 \ J = 99,000 \ J$.

The pressure of a gas is $100 \ kPa$. If it is compressed from $1 \ m^{3}$ to $10 \ dm^{3}$,find the work done. (in $J$)

Similar Questions

The enthalpies of the elements in their standard states are assumed to be

The volume of $100 \ L$ of gas increases to $120 \ L$ at a constant temperature and an external pressure of $10 \ bar$. Calculate the work done by the system. [Given: $1 \ L \ bar = 24.21 \ cal$] (in $cal$)

Which among the following is $NOT$ an intensive property?

Which of the following is not an extensive property?

Prove that the change in enthalpy of a system in which a chemical reaction occurs is equal to the heat gained by the system at constant pressure.

Vedclass Test Series

Exam Paper Generator

Online Exam Module