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(D) Let the original price of the article be $x$.First,the price is increased by $10 \%$,so the new price becomes $x 	imes (1 + 0.10) = 1.1x$.Then,th

Vedclass · Accepted Answer

$25$

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(D) Let the original price of the article be $x$.First,the price is increased by $10 \%$,so the new price becomes $x 	imes (1 + 0.10) = 1.1x$.Then,this price is increased by $20 \%$,so the final price becomes $1.1x 	imes (1 + 0.20) = 1.1x 	imes 1.2 = 1.32x$.Given that the final price is $₹ 33$,we have the equation:$1.32x = 33$$x = \frac{33}{1.32}$$x = \frac{3300}{132} = 25$.Therefore,the original price was $₹ 25$.

The price of an article was first increased by $10 \%$ and then again by $20 \%$. If the final increased price is $₹ 33$,what was the original price?

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