The principal reason that the melting point of $NaF$ is much higher than that of $RbBr$ is that

  • A
    the two crystals are not isomorphs
  • B
    the molar mass of $NaF$ is smaller than that of $RbBr$
  • C
    the bond in $RbBr$ has more covalent character than the bond in $NaF$
  • D
    the internuclear distance $(r^+ + r^-)$ is greater for $RbBr$ than for $NaF$

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