The probabilities of having a defective toy in three cartons $A, B, C$ are $\frac{1}{3}, \frac{1}{4}, \frac{2}{5}$ respectively. If a carton is selected at random and a toy drawn randomly from it is found to be defective,then the probability that it is drawn from carton $B$ is

  • A
    $\frac{15}{47}$
  • B
    $\frac{20}{47}$
  • C
    $\frac{20}{59}$
  • D
    $\frac{15}{59}$

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