The probability of a non-leap year having $53$ Saturdays is .......

  • A
    $1$
  • B
    $\frac{1}{2}$
  • C
    $\frac{1}{7}$
  • D
    $\frac{2}{7}$

Explore More

Similar Questions

$A$ card is drawn at random from a well-shuffled pack of $52$ cards. The probability of that card being a jack of a black suit is .........

Find the probability of getting number $2$ on a die when a fair die is thrown.

$I$ toss three coins together. The possible outcomes are no heads,$1$ head,$2$ heads and $3$ heads. So,$I$ say that probability of no heads is $\frac{1}{4}$. What is wrong with this conclusion?

Two balanced dice are rolled simultaneously. Then,the probability that the numbers appearing on both the dice are different is ........

Difficult
View Solution

If $P(A) : P(\bar{A}) = 3 : 2$,then $P(A) = \dots$

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo