The probability of forming a $12$-person committee from $4$ engineers,$2$ doctors,and $10$ professors containing at least $3$ engineers and at least $1$ doctor is:

  • A
    $\frac{129}{182}$
  • B
    $\frac{103}{182}$
  • C
    $\frac{17}{26}$
  • D
    $\frac{19}{26}$

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