The probability that a non-leap year contains | vedclass

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(A) non-leap year contains $365$ days,which is equal to $52$ weeks and $1$ extra day.Since there are $52$ weeks,there are definitely $52$ Sundays.For

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$\frac{1}{7}$

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(A) non-leap year contains $365$ days,which is equal to $52$ weeks and $1$ extra day.Since there are $52$ weeks,there are definitely $52$ Sundays.For the year to have $53$ Sundays,the extra day must be a Sunday.The set of possible outcomes for the extra day is $\{ 	ext{Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday} \}$.Total number of possible outcomes $= 7$.Number of favorable outcomes (the day being a Sunday) $= 1$.Therefore,the probability $= \frac{	ext{Number of favorable outcomes}}{	ext{Total number of outcomes}} = \frac{1}{7}$.

The probability that a non-leap year contains $53$ Sundays is

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