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(C) The reaction involves the electrophilic addition of $HBr$ to $1,2-dimethylcyclohexene$. First,the protonation of the double bond occurs to form a

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a pair of diastereomers

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(C) The reaction involves the electrophilic addition of $HBr$ to $1,2-dimethylcyclohexene$. First,the protonation of the double bond occurs to form a carbocation intermediate. Since the starting material is chiral ($1-methyl-2-methylcyclohexene$ with a fixed stereocenter),the addition of the bromide ion can occur from either the top or bottom face of the planar carbocation. This results in the formation of two new stereocenters,leading to the creation of two diastereomers,as the existing stereocenter remains unchanged while a new one is formed at the carbon where the bromine attaches.

The product $(s)$ of the following reaction can best be described as

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