The product A formed in the following reactio | vedclass

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(C) The reaction sequence is as follows:$1$. Aniline $(C_6H_5NH_2)$ reacts with $NaNO_2$ and $HCl$ at $0-5 \ ^{\circ}C$ to form benzenediazonium chlor

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Chlorobenzene

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(C) The reaction sequence is as follows:$1$. Aniline $(C_6H_5NH_2)$ reacts with $NaNO_2$ and $HCl$ at $0-5 \ ^{\circ}C$ to form benzenediazonium chloride $(C_6H_5N_2^+Cl^-)$. This is known as the diazotization reaction.$2$. The benzenediazonium chloride then reacts with $Cu_2Cl_2$ (cuprous chloride) to form chlorobenzene $(C_6H_5Cl)$. This is a classic Sandmeyer reaction.Therefore,the final product $A$ is chlorobenzene.

The product $A$ formed in the following reaction is:

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Consider the reaction shown below. Compound $B$ is:

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