The product (C) in the following reaction seq | vedclass

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(D) $1$. The reaction of $4-	ext{bromoethylbenzene}$ with $Br_2$ in the presence of heat $(\Delta)$ undergoes free-radical substitution at the benzyl

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$1-$($4$-Bromophenyl)ethanol

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(D) $1$. The reaction of $4-	ext{bromoethylbenzene}$ with $Br_2$ in the presence of heat $(\Delta)$ undergoes free-radical substitution at the benzylic position to form $1-(4-	ext{bromophenyl})	ext{bromoethane}$ (compound $B$). $2$. The subsequent reaction of compound $B$ with aqueous $KOH$ is a nucleophilic substitution reaction ($S_N1$ or $S_N2$),where the bromine atom at the benzylic position is replaced by a hydroxyl group $(-OH)$ to form $1-(4-	ext{bromophenyl})	ext{ethanol}$ (compound $C$).

The product $(C)$ in the following reaction sequence is:
$4-\text{Bromoethylbenzene}$ $\xrightarrow[\Delta]{Br_2} B$ $\xrightarrow{\text{aq. } KOH} C$

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The product $(C)$ in the following reaction sequence is: $4-\text{Bromoethylbenzene}$ $\xrightarrow[\Delta]{Br_2} B$ $\xrightarrow{\text{aq. } KOH} C$