(A) Step $1$: Aniline reacts with acetic anhydride $(CH_3CO)_2O$ in the presence of pyridine to form acetanilide $(C_6H_5NHCOCH_3)$.Step $2$: Acetanil

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(A) Step $1$: Aniline reacts with acetic anhydride $(CH_3CO)_2O$ in the presence of pyridine to form acetanilide $(C_6H_5NHCOCH_3)$.Step $2$: Acetanilide is then reduced by $LiAlH_4$ (a strong reducing agent) which reduces the amide group $(-NHCOCH_3)$ to an amine group $(-NHCH_2CH_3)$.Step $3$: Hydrolysis $(H_2O)$ yields the final product,$N$-ethylaniline $(C_6H_5NHCH_2CH_3)$.

Class 12 Chemistry Amines Properties of Amines

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The product formed from the following reaction sequence is:

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A
$N$-ethylaniline
B
$2-(1$-hydroxyethyl)aniline
C
$4-(1$-hydroxyethyl)aniline
D
$2,4$-bis($1$-hydroxyethyl)aniline

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The product formed from the following reaction sequence is:

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$H_3CCONH_2 + Br_2 + 4NaOH \longrightarrow Y + Na_2CO_3 + 2NaBr + 2H_2O$What is $Y$ in the above reaction?

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Identify the products $y$ and $x$ in the following reaction sequence:$C_6H_5CONH_2 \xrightarrow{NaOBr} y$$C_6H_5CONH_2 \xrightarrow[(ii) H_3O^+]{(i) C_6H_5SO_2Cl / py, \Delta} x$

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$H_3CCONH_2 + Br_2 + 4NaOH \longrightarrow Y + Na_2CO_3 + 2NaBr + 2H_2O$
What is $Y$ in the above reaction?

Identify the products $y$ and $x$ in the following reaction sequence:
$C_6H_5CONH_2 \xrightarrow{NaOBr} y$
$C_6H_5CONH_2 \xrightarrow[(ii) H_3O^+]{(i) C_6H_5SO_2Cl / py, \Delta} x$