The product obtained from the electrolytic ox | vedclass

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Question

(B) During the electrolysis of a concentrated acidified sulphate solution,the oxidation of sulphate ions occurs at the anode.The anode reaction is: $2

Vedclass · Accepted Answer

$H_{2}S_{2}O_{8}$

Vedclass · Answer

(B) During the electrolysis of a concentrated acidified sulphate solution,the oxidation of sulphate ions occurs at the anode.The anode reaction is: $2S{O_{4}}^{2-}_{(aq)} \rightarrow S_{2}{O_{8}}^{2-}_{(aq)} + 2e^{-}$.The cathode reaction is: $2H^{+}_{(aq)} + 2e^{-} \rightarrow H_{2(g)}$.The resulting peroxodisulphuric acid $(H_{2}S_{2}O_{8})$ is formed by the combination of $S_{2}O_{8}^{2-}$ ions with $H^{+}$ ions in the solution.

The product obtained from the electrolytic oxidation of acidified sulphate solution is:

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