The product of the following reaction is C_6H | vedclass

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Question

(A) The reaction is a Claisen-Schmidt condensation,which is a type of crossed aldol condensation between benzaldehyde (which has no $\alpha$-hydrogens

Vedclass · Accepted Answer

$C_6H_5CH=C(CH_3)CHO$

Vedclass · Answer

(A) The reaction is a Claisen-Schmidt condensation,which is a type of crossed aldol condensation between benzaldehyde (which has no $\alpha$-hydrogens) and propanal (which has $\alpha$-hydrogens). In the presence of dilute $NaOH$,the $\alpha$-carbon of propanal acts as a nucleophile and attacks the carbonyl carbon of benzaldehyde to form an aldol intermediate. Subsequent dehydration (loss of $H_2O$) under heating $(\Delta)$ yields the $\alpha,\beta$-unsaturated aldehyde,$C_6H_5CH=C(CH_3)CHO$. Thus,the correct product is $C_6H_5CH=C(CH_3)CHO$.

The product of the following reaction is $C_6H_5CHO + CH_3CH_2CHO \xrightarrow[\Delta]{\text{Dil. NaOH}}$

Similar Questions

The major product formed in the following reaction is:

The major product $(Z)$ of the following chemical reaction is

End products of the following sequence of reactions are:

Which among the following reagents cannot be used for the above interconversion? The reaction involves the reduction of a ketone group $(>C=O)$ to a methylene group $(-CH_2-)$.

The reaction sequence is as follows:
$Cyclopentanecarboxamide$ $\xrightarrow{P_2O_5, \Delta} W$ $\xrightarrow{CH_3MgBr, H_3^+O} X$ $\xrightarrow{Ca(OH)_2, I_2 (\text{yellow ppt.})} Y$ $\xrightarrow{\Delta} Z$
$Z$ is:

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