The product of the reaction between ammonia and formaldehyde is

Identify the product $A$ in the following reaction:
$\text{Substrate} \xrightarrow{MnO_2} A$
(The substrate is a benzene ring with a $-OH$ group,a $-COOH$ group,and a $-CH(CH_2CH_3)CHO$ group attached to it.)

$CH_3-CHO + HCN \to A$; Compound $A$ on hydrolysis gives

$\text{Phthalic anhydride}$ $\xrightarrow {PCl_5} A$ $\xrightarrow {LiAlH_4} B$ $\xrightarrow {PCC} C$ $\xrightarrow [\Delta ] {OH^{-}} D$
Compound $D$ is :-

Assertion: Acetoacetic ester,$CH_3COCH_2COOC_2H_5$,will give iodoform test.
Reason: It does not contain $CH_3CO-$ group.

Cyclopentanone $\xrightarrow[\text{traces of } KOH]{HCN} A$ $\xrightarrow{LiAlH_4} B$ $\xrightarrow{NaNO_2, HCl} C$
$C$ is