The product of the reaction between ethylbenz | vedclass

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Question

(B) $N$-bromosuccinimide $(NBS)$ is a reagent used for allylic or benzylic bromination via a free radical mechanism.In ethylbenzene $(C_6H_5CH_2CH_3)$

Vedclass · Accepted Answer

$1-$bromo$-1-$phenylethane

Vedclass · Answer

(B) $N$-bromosuccinimide $(NBS)$ is a reagent used for allylic or benzylic bromination via a free radical mechanism.In ethylbenzene $(C_6H_5CH_2CH_3)$,the benzylic position is the carbon atom directly attached to the benzene ring.The hydrogen atoms at the benzylic position are more reactive due to the stability of the resulting benzylic radical.Therefore,$NBS$ selectively replaces a hydrogen atom at the benzylic position with a bromine atom,yielding $1$-bromo-$1$-phenylethane $(C_6H_5CH(Br)CH_3)$.

The product of the reaction between ethylbenzene and $N$-bromosuccinimide $(NBS)$ is:

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