The product of the reaction is

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(A) The reaction involves the treatment of $2$-bromobenzyl chloride with ammonia $(NH_3)$ in ethanol $(EtOH)$. This is a nucleophilic substitution rea

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$2-$bromobenzylamine

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(A) The reaction involves the treatment of $2$-bromobenzyl chloride with ammonia $(NH_3)$ in ethanol $(EtOH)$. This is a nucleophilic substitution reaction $(S_N2)$ where the nucleophile $NH_3$ attacks the electrophilic carbon of the $-CH_2Cl$ group, displacing the chloride ion $(Cl^-)$. The bromine atom attached to the benzene ring is relatively inert towards nucleophilic substitution under these conditions. Therefore, the $-CH_2Cl$ group is converted into a $-CH_2NH_2$ group, resulting in the formation of $2$-bromobenzylamine.

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