The product of uncertainty in the position and uncertainty in the velocity of a particle is $5.79 \times 10^{-5} \ m^2 \ s^{-1}$. If the uncertainty in the position is $1 \ nm$, what is the uncertainty in the measurement of its velocity in $m \ s^{-1}$?

  • A
    $5.79 \times 10^7$
  • B
    $5.79 \times 10^5$
  • C
    $5.79 \times 10^{-5}$
  • D
    $5.79 \times 10^4$

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If the uncertainty in velocity and position of a minute particle in space are $2.4 \times 10^{-26} \, m \, s^{-1}$ and $10^{-7} \, m$ respectively,the mass of the particle in $g$ is $....$ (Nearest integer).
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If the position of the electron is measured within an accuracy of $\pm 0.002 \,nm$,calculate the uncertainty in the momentum of the electron. Suppose the momentum of the electron is $\frac{h}{4 \pi \times 0.05 \,nm}$,is there any problem in defining this value?

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For an electron,if the uncertainty in velocity is $\Delta \nu$,the uncertainty in its position $(\Delta x)$ is given by:

The uncertainty in position and velocity of a particle in motion are $1 \times 10^{-8} \ m$ and $6.627 \times 10^{-20} \ m/s$, respectively. The mass of the particle is $(h = 6.627 \times 10^{-34} \ J \cdot s)$

What is the value of $\Delta v \cdot \Delta x$ for an electron? What does it indicate?

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