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(C) The $S_N 1$ mechanism proceeds via the formation of a stable carbocation intermediate. The stability of the carbocation determines the ease of the

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$B, C$ only

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(C) The $S_N 1$ mechanism proceeds via the formation of a stable carbocation intermediate. The stability of the carbocation determines the ease of the $S_N 1$ reaction. Benzylic carbocations are highly stable due to resonance.$(A)$ The product is $C_6H_5CH_2CH_2CH_2Cl$ (a primary alkyl halide),which undergoes hydrolysis via $S_N 2$.$(B)$ The product is $C_6H_5CH(Br)CH_2CH_3$,which forms a stable benzylic carbocation $(C_6H_5CH^+CH_2CH_3)$ upon ionization,thus favoring $S_N 1$.$(C)$ The product is $C_6H_5C(Br)(CH_3)_2$,which forms a stable benzylic carbocation $(C_6H_5C^+(CH_3)_2)$ upon ionization,thus favoring $S_N 1$.$(D)$ The product is $C_6H_5CH_2CH_2Br$ (a primary alkyl halide),which undergoes hydrolysis via $S_N 2$.Therefore,only $(B)$ and $(C)$ form stable benzylic carbocations and undergo hydrolysis by the $S_N 1$ mechanism.

The product of which of the following reactions undergoes hydrolysis by the $S_N 1$ mechanism?

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