The products $A$ and $B$ in the following reaction sequence are:

  • A
    $A$ = $3-$phenylpropanoic acid; $B$ = $N$-methyl$-3-$phenylpropanamide
  • B
    $A$ = $2-$phenylpropanoic acid; $B$ = $N$-methyl$-2-$phenylpropanamide
  • C
    $A$ = $2-$phenylethanol; $B$ = $N$-methyl$-2-$phenylethanamine
  • D
    $A$ = $1-$phenylethanol; $B$ = $N$-methyl$-1-$phenylethanamine

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Similar Questions

What is the product of the following reaction?

The product $D$ of the reaction is:
$CH_3Cl$ $\xrightarrow{KCN} (A)$ $\xrightarrow{H_2O} (B)$ $\xrightarrow{NH_3} (C)$ $\xrightarrow{\Delta} (D)$

Saponification (basic hydrolysis) of $C_6H_5-CO-^{18}OCH_3$ will yield. [$^{18}O$ = mass $-18$ isotope of oxygen]

Statement $(A)$: Carboxylic acid can be obtained by the reaction of $R-C \equiv N$ with $H_3O^+$ under mild reaction conditions.
Statement $(B)$: Hydrolysis of $R-C \equiv N$ in alkaline aqueous medium gives $R-COONa$ and $NH_3$ as products.
The correct answer is:

Match the formulas in Column-$I$ with their names in Column-$II$.
Column-$I$ (formula) Column-$II$ (name)
$A$. $RCH=NH$ $i$. Diisobutyl aluminium hydride
$B$. $AlH(i-Bu)_2$ $ii$. Benzalchloride
$C$. $C_6H_5-CH(OCOCH_3)_2$ $iii$. Imine
$D$. $C_6H_5CHCl_2$ $iv$. Benzylidene diacetate

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