The products P and Q of the following reactio | vedclass

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(A) The reaction of sulphur $(S_8)$ with hot aqueous sodium hydroxide $(NaOH)$ is a disproportionation reaction. In this reaction, sulphur is both oxi

Vedclass · Accepted Answer

$Na_2S; Na_2S_2O_3$

Vedclass · Answer

(A) The reaction of sulphur $(S_8)$ with hot aqueous sodium hydroxide $(NaOH)$ is a disproportionation reaction. In this reaction, sulphur is both oxidized and reduced to form sodium sulfide $(Na_2S)$ and sodium thiosulphate $(Na_2S_2O_3)$. The balanced chemical equation is: $S_8 + 12 NaOH \longrightarrow 4 Na_2S + 2 Na_2S_2O_3 + 6 H_2O$. Thus, the products $P$ and $Q$ are $Na_2S$ and $Na_2S_2O_3$ respectively.

The products $P$ and $Q$ of the following reaction, respectively, are $a S_{8(s)} + b NaOH_{(aq)} \longrightarrow P_{(aq)} + q Q_{(aq)} + r H_2O$

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$S_8 + NaOH \longrightarrow Na_2S + Na_2S_2O_3$

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