The proposition p rightarrow sim( p wedge sim | vedclass

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Question

(A) Given the proposition: $p \rightarrow \sim( p \wedge \sim q )$Using the implication law $A \rightarrow B \equiv \sim A \vee B$,we get:$\sim p \vee

Vedclass · Accepted Answer

$(\sim p) \vee q$

Vedclass · Answer

(A) Given the proposition: $p \rightarrow \sim( p \wedge \sim q )$Using the implication law $A \rightarrow B \equiv \sim A \vee B$,we get:$\sim p \vee \sim( p \wedge \sim q )$Applying De Morgan's Law $\sim( A \wedge B ) \equiv \sim A \vee \sim B$:$\sim p \vee (\sim p \vee \sim(\sim q))$Since $\sim(\sim q) \equiv q$:$\sim p \vee \sim p \vee q$Using the idempotent law $\sim p \vee \sim p \equiv \sim p$:$\sim p \vee q$Thus,the proposition is equivalent to $(\sim p) \vee q$.

The proposition $p \rightarrow \sim( p \wedge \sim q )$ is equivalent to

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