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(C) Given the relation $m = A/B$,we can express $B$ as $B = A/m$.Linear density $m$ is defined as mass per unit length,so its dimensions are $[M L^{-1

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Latent heat

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(C) Given the relation $m = A/B$,we can express $B$ as $B = A/m$.Linear density $m$ is defined as mass per unit length,so its dimensions are $[M L^{-1}]$.Force $A$ has dimensions $[M L T^{-2}]$.Substituting these into the expression for $B$:$[B] = \frac{[M L T^{-2}]}{[M L^{-1}]} = [L^2 T^{-2}]$.Latent heat $L$ is defined as energy per unit mass,so its dimensions are $[M L^2 T^{-2}] / [M] = [L^2 T^{-2}]$.Thus,the dimensions of $B$ are the same as those of latent heat.

Column-$I$	Column-$II$
$(a)$ Viscous force	$(i)$ $[M^1 L^1 T^{-2}]$
$(b)$ Coefficient of viscosity	$(ii)$ $[M^1 L^{-1} T^{-1}]$
	$(iii)$ $[M^1 L^{-1} T^{-2}]$

The quantities $A$ and $B$ are related by the relation $m = A/B$,where $m$ is the linear density and $A$ is the force. The dimensions of $B$ are of

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