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(A) The orbital speed $v$ of a satellite at a distance $r$ from the center of the earth is given by the formula $v = \sqrt{\frac{GM}{r}}$.From this re

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$3V$

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(A) The orbital speed $v$ of a satellite at a distance $r$ from the center of the earth is given by the formula $v = \sqrt{\frac{GM}{r}}$.From this relation,we can see that $v \propto \frac{1}{\sqrt{r}}$.Let $v_A$ and $v_B$ be the speeds of satellites $A$ and $B$ with orbital radii $r_A = 4R$ and $r_B = R$ respectively.Taking the ratio,we get $\frac{v_A}{v_B} = \sqrt{\frac{r_B}{r_A}}$.Substituting the given values,$\frac{v_A}{6V} = \sqrt{\frac{R}{4R}} = \sqrt{\frac{1}{4}} = \frac{1}{2}$.Therefore,$v_A = 6V 	imes \frac{1}{2} = 3V$.

The radii of circular orbits of two satellites $A$ and $B$ of the earth are $4R$ and $R$ respectively,where $R$ is the radius of the earth. If the speed of satellite $B$ is $6V$,then the speed of satellite $A$ will be:

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