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(B) The capacitance $C$ of a spherical capacitor with a dielectric medium is given by $C = K \cdot 4\pi \varepsilon_0 \left( \frac{r_1 r_2}{r_2 - r_1}

Vedclass · Accepted Answer

$30$

Vedclass · Answer

(B) The capacitance $C$ of a spherical capacitor with a dielectric medium is given by $C = K \cdot 4\pi \varepsilon_0 \left( \frac{r_1 r_2}{r_2 - r_1} ight)$.Given: $r_1 = 9 	imes 10^{-2}\,m$,$r_2 = 10 	imes 10^{-2}\,m$,$K = 6$,and $q = 18 	imes 10^{-9}\,C$.Substituting the values: $C = 6 	imes \frac{1}{9 	imes 10^9} 	imes \left( \frac{9 	imes 10^{-2} 	imes 10 	imes 10^{-2}}{10 	imes 10^{-2} - 9 	imes 10^{-2}} ight)$.$C = \frac{6}{9 	imes 10^9} 	imes \left( \frac{90 	imes 10^{-4}}{1 	imes 10^{-2}} ight) = \frac{6}{9 	imes 10^9} 	imes 90 	imes 10^{-2} = 6 	imes 10^{-10}\,F$.The potential $V$ of the inner sphere relative to the earthed outer sphere is $V = \frac{q}{C}$.$V = \frac{18 	imes 10^{-9}}{6 	imes 10^{-10}} = 3 	imes 10 = 30\,V$.

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