The radii of two mercury drops are $R_1$ and $R_2$. Under isothermal conditions,a single drop of radius $R$ is formed from them. The relation between $R, R_1$ and $R_2$ is

  • A
    $R^2=R_1^2+R_2^2$
  • B
    $R=R_1+R_2$
  • C
    $R=\frac{R_1+R_2}{2}$
  • D
    $R^3=R_1^3+R_2^3$

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