The radioactive decay of uranium into thorium | vedclass

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(D) In a radioactive decay process,both the mass number $(A)$ and the atomic number $(Z)$ must be conserved.For the given reaction: $_{92}^{238}U 	o

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An alpha particle

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(D) In a radioactive decay process,both the mass number $(A)$ and the atomic number $(Z)$ must be conserved.For the given reaction: $_{92}^{238}U 	o _{90}^{234}Th + _{Z}^{A}X$Conservation of mass number: $238 = 234 + A \implies A = 4$Conservation of atomic number: $92 = 90 + Z \implies Z = 2$The particle with mass number $4$ and atomic number $2$ is a helium nucleus $(_{2}^{4}He)$,which is an alpha particle.Therefore,$X = _{2}^{4}He$ (alpha particle).

The radioactive decay of uranium into thorium is expressed by the equation $_{92}^{238}U \to _{90}^{234}Th + X,$ where $X$ is

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