The radionuclide _{90}^{234}Th undergoes two | vedclass

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(C) The initial radionuclide is $_{90}^{234}Th$. $1$. First $\beta$-decay: $_{90}^{234}Th \rightarrow {}_{91}^{234}X + {}_{-1}^{0}e$. $2$. Second $\be

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$90$ and $230$

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(C) The initial radionuclide is $_{90}^{234}Th$. $1$. First $\beta$-decay: $_{90}^{234}Th \rightarrow {}_{91}^{234}X + {}_{-1}^{0}e$. $2$. Second $\beta$-decay: $_{91}^{234}X \rightarrow {}_{92}^{234}Y + {}_{-1}^{0}e$. $3$. One $\alpha$-decay: $_{92}^{234}Y \rightarrow {}_{90}^{230}Z + {}_{2}^{4}He$. Thus,the resulting radionuclide has an atomic number of $90$ and a mass number of $230$.

The radionuclide $_{90}^{234}Th$ undergoes two successive $\beta$-decays followed by one $\alpha$-decay. The atomic number and the mass number respectively of the resulting radionuclide are

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