The radius of a hemispherical dome of a templ | vedclass

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(D) The radius $(r)$ of the hemispherical dome is $21\, m$.The curved surface area $(CSA)$ of a hemisphere is given by the formula $2\pi r^2$.$CSA = 2

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$221760$

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(D) The radius $(r)$ of the hemispherical dome is $21\, m$.The curved surface area $(CSA)$ of a hemisphere is given by the formula $2\pi r^2$.$CSA = 2 	imes \frac{22}{7} 	imes 21 	imes 21$$CSA = 2 	imes 22 	imes 3 	imes 21$$CSA = 44 	imes 63 = 2772\, m^2$.The cost of painting is ₹ $80$ per $m^2$.Total cost = $CSA 	imes 	ext{Rate} = 2772 	imes 80 = 2,21,760$.Thus,the total cost of painting the outer surface is ₹ $2,21,760$.

The radius of a hemispherical dome of a temple is $21\, m$. Find the cost of painting its outer surface at the rate of ₹ $80/m^2$. (in ₹)

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