The radius of a sphere is (5.3 pm 0.1) , cm. | vedclass

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(B) The volume of a sphere is given by $V = \frac{4}{3} \pi r^3$.The relative error in volume is given by $\frac{\Delta V}{V} = 3 \frac{\Delta r}{r}$.

Vedclass · Accepted Answer

$3 	imes \frac{0.1}{5.3} 	imes 100$

Vedclass · Answer

(B) The volume of a sphere is given by $V = \frac{4}{3} \pi r^3$.The relative error in volume is given by $\frac{\Delta V}{V} = 3 \frac{\Delta r}{r}$.To find the percentage error,we multiply by $100$:$	ext{Percentage error in volume} = 3 	imes \left( \frac{\Delta r}{r} ight) 	imes 100$.Given $r = 5.3 \, cm$ and $\Delta r = 0.1 \, cm$,we substitute these values:$	ext{Percentage error} = 3 	imes \left( \frac{0.1}{5.3} ight) 	imes 100$.Thus,the correct option is $B$.

The radius of a sphere is $(5.3 \pm 0.1) \, cm$. The percentage error in its volume is

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