The radius of Earth is about 6400 ,km and tha | vedclass

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(A) Given: Radius of Earth $(R_e)$ $= 6400 \,km$,Radius of Mars $(R_m)$ $= 3200 \,km$.Mass of Earth $(M_e)$ $= 10 M_m$,where $M_m$ is the mass of Mars

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$80$

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(A) Given: Radius of Earth $(R_e)$ $= 6400 \,km$,Radius of Mars $(R_m)$ $= 3200 \,km$.Mass of Earth $(M_e)$ $= 10 M_m$,where $M_m$ is the mass of Mars.The acceleration due to gravity on the surface of a planet is given by $g = \frac{GM}{R^2}$.The ratio of acceleration due to gravity on Mars $(g_m)$ to that on Earth $(g_e)$ is:$\frac{g_m}{g_e} = \frac{G M_m / R_m^2}{G M_e / R_e^2} = \frac{M_m}{M_e} 	imes \left(\frac{R_e}{R_m}ight)^2$.Substituting the given values:$\frac{g_m}{g_e} = \frac{1}{10} 	imes \left(\frac{6400}{3200}ight)^2 = \frac{1}{10} 	imes (2)^2 = \frac{4}{10} = \frac{2}{5}$.The weight of an object is $W = mg$.Given weight on Earth $W_e = m g_e = 200 \,N$.Weight on Mars $W_m = m g_m = m \left(\frac{2}{5} g_eight) = \frac{2}{5} W_e$.$W_m = \frac{2}{5} 	imes 200 \,N = 80 \,N$.

The radius of Earth is about $6400 \,km$ and that of Mars is $3200 \,km$,and the mass of the Earth is about $10$ times the mass of Mars. An object weighs $200 \,N$ on the surface of Earth. Then,its weight on the surface of Mars will be (in $\,N$)

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