The range of a discrete random variable $X$ is $\{1, 2, 3\}$ and the probabilities of its elements are given by $P(X=1) = 3k^3$, $P(X=2) = 2k^2$, and $P(X=3) = 7 - 19k$. Then $P(X=3) = $

  • A
    $\frac{2}{3}$
  • B
    $\frac{2}{9}$
  • C
    $\frac{1}{9}$
  • D
    $\frac{4}{9}$

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