(D) The Arrhenius equation is given by: $\log K = \log A - \frac{E_a}{2.303 RT}$ Given: $A = 1.45 \times 10^{11} s^{-1}$,$E_a = 35 \times 10^3 \, cal\

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

(D) The Arrhenius equation is given by: $\log K = \log A - \frac{E_a}{2.303 RT}$ Given: $A = 1.45 \times 10^{11} s^{-1}$,$E_a = 35 \times 10^3 \, cal\, mol^{-1}$,$T = 300 + 273 = 573 \, K$,$R = 1.987 \approx 2 \, cal\, K^{-1} mol^{-1}$ Substituting the values: $\log K = \log (1.45 \times 10^{11}) - \frac{35000}{2.303 \times 2 \times 573}$ $\log K = 11.161 - \frac{35000}{2640.038} \approx 11.161 - 13.257 = -2.096$ $K = \text{antilog}(-2.096) = 7.94 \times 10^{-3} s^{-1}$

Class 12 Chemistry Chemical Kinetics Collision theory, Energy of activation and Arrhenius equation

Medium

The rate constant for a first order reaction at $300\, ^\circ C$ for which $E_a$ is $35\, kcal\, mol^{-1}$ and frequency constant $(A)$ is $1.45 \times 10^{11} s^{-1}$ will be:

A
$10 \times 10^{-2} s^{-1}$
B
$5.37 \times 10^{10} s^{-1}$
C
$5 \times 10^{-4} s^{-1}$
D
$7.94 \times 10^{-3} s^{-1}$

Explore More

Browse All

Question Bank

All Subjects

Class 12 Questions

Class 12

Chemistry Questions

Chapter

Chemical Kinetics

Subtopic

Collision theory, Energy of activation and Arrhenius equation

Which of the following statements is true for a catalyst?

Easy

View Solution

The activation energy for the reaction $2 HI_{(g)} \rightarrow H_{2(g)} + I_{2(g)}$ is $209.5 \ kJ \ mol^{-1}$ at $581 \ K$. Calculate the fraction of molecules of reactants having energy equal to or greater than activation energy?

Difficult

View Solution

The Arrhenius equation can be represented as:

Easy

View Solution

For reactions $M, N, O$ and $P$,the activation energy order is $E_M < E_N < E_O < E_P$. For which reaction will the ratio $K_{310}/K_{300}$ be maximum?

Medium

View Solution

$A$ reaction has an activation energy of $209 \, kJ \, mol^{-1}$. The rate increases $10$-fold when the temperature is increased from $27^{\circ} C$ to $X^{\circ} C$. The temperature $X$ is closest to
[Gas constant,$R = 8.314 \, J \, mol^{-1} \, K^{-1}$ ]

MediumKVPY 2017

View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial

For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free

For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo

The rate constant for a first order reaction at $300\, ^\circ C$ for which $E_a$ is $35\, kcal\, mol^{-1}$ and frequency constant $(A)$ is $1.45 \times 10^{11} s^{-1}$ will be:

Similar Questions

Which of the following statements is true for a catalyst?

The activation energy for the reaction $2 HI_{(g)} \rightarrow H_{2(g)} + I_{2(g)}$ is $209.5 \ kJ \ mol^{-1}$ at $581 \ K$. Calculate the fraction of molecules of reactants having energy equal to or greater than activation energy?

The Arrhenius equation can be represented as:

For reactions $M, N, O$ and $P$,the activation energy order is $E_M < E_N < E_O < E_P$. For which reaction will the ratio $K_{310}/K_{300}$ be maximum?

$A$ reaction has an activation energy of $209 \, kJ \, mol^{-1}$. The rate increases $10$-fold when the temperature is increased from $27^{\circ} C$ to $X^{\circ} C$. The temperature $X$ is closest to[Gas constant,$R = 8.314 \, J \, mol^{-1} \, K^{-1}$ ]

Vedclass Test Series

Exam Paper Generator

Online Exam Module

$A$ reaction has an activation energy of $209 \, kJ \, mol^{-1}$. The rate increases $10$-fold when the temperature is increased from $27^{\circ} C$ to $X^{\circ} C$. The temperature $X$ is closest to
[Gas constant,$R = 8.314 \, J \, mol^{-1} \, K^{-1}$ ]