The rate law equation for a reaction is $R = k[x][y]$. The rate of reaction doubles when:

  • A
    concentration of $x$ is kept constant and concentration of $y$ is halved
  • B
    concentration of both $x$ and $y$ is doubled
  • C
    concentration of $x$ is doubled and concentration of $y$ is kept constant
  • D
    concentration of $y$ is doubled and concentration of $x$ is halved

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Similar Questions

The following graph shows how $T_{1/2}$ (half-life) of a reactant $R$ changes with the initial reactant concentration $a_0$. The order of the reaction will be:

What is the time taken for the $3^{rd}$ half-life of a second-order decomposition reaction,given that its first half-life is $20 \ s$ (in $s$)?

The results given in the below table were obtained during kinetic studies of the following reaction:
$2 A + B \longrightarrow C + D$
Experiment $[A] / mol \ L^{-1}$ $[B] / mol \ L^{-1}$ Initial rate / $mol \ L^{-1} \ min^{-1}$
$I$ $0.1$ $0.1$ $6.00 \times 10^{-3}$
$II$ $0.1$ $0.2$ $2.40 \times 10^{-2}$
$III$ $0.2$ $0.1$ $1.20 \times 10^{-2}$
$IV$ $X$ $0.2$ $7.20 \times 10^{-2}$
$V$ $0.3$ $Y$ $2.88 \times 10^{-1}$

$X$ and $Y$ in the given table are respectively :

For the reaction $X_{2(g)} + Y_{2(g)} \rightarrow 2XY_{(g)}$,the following data are observed:
$[X_{2}] \ (M)$$[Y_{2}] \ (M)$Rate of appearance of $XY \ (M \ sec^{-1})$
$0.1$$0.1$$5 \times 10^{-6}$
$0.2$$0.1$$10^{-5}$
$0.2$$0.2$$4 \times 10^{-5}$

Calculate the rate constant of the reaction (in $M^{1-n} \ sec^{-1}$),where $n$ is the order of the reaction.

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Give the relation between half-life $(t_{1/2})$ and initial concentration of reactant $([R]_0)$ for an $(n-1)^{th}$ order reaction.

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