The rate of S_N1 reaction will be faster for | vedclass

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(A) The rate of $S_N1$ reaction depends on the stability of the carbocation intermediate formed in the rate-determining step.In $Ph_2CHBr$,the carboca

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$Ph_2CHBr$

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(A) The rate of $S_N1$ reaction depends on the stability of the carbocation intermediate formed in the rate-determining step.In $Ph_2CHBr$,the carbocation formed is $Ph_2CH^+$,which is a benzhydryl carbocation. This carbocation is highly stabilized by resonance delocalization of the positive charge over two benzene rings.Comparing the stability of carbocations:$1$. $Ph_2CH^+$ (benzhydryl,stabilized by two phenyl rings)$2$. $Ph-C_6H_4-CH_2^+$ (stabilized by one phenyl ring)$3$. $Ph-CH^+(CH_3)$ (secondary benzylic,stabilized by one phenyl ring)$4$. $(CH_3)_2CH^+$ (secondary alkyl,no resonance stabilization)The $Ph_2CH^+$ carbocation is the most stable among the given options,therefore $Ph_2CHBr$ will undergo $S_N1$ reaction the fastest.

The rate of $S_N1$ reaction will be faster for which of the following bromides?

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