The rate of diffusion of SO_2,CO_2,PCl_3 and | vedclass

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Question

(B) According to Graham's law of diffusion,the rate of diffusion $(r)$ is inversely proportional to the square root of the molar mass $(M)$: $r \propt

Vedclass · Accepted Answer

$CO_2 > SO_2 > SO_3 > PCl_3$

Vedclass · Answer

(B) According to Graham's law of diffusion,the rate of diffusion $(r)$ is inversely proportional to the square root of the molar mass $(M)$: $r \propto \frac{1}{\sqrt{M}}$.First,calculate the molar masses $(M)$ of the given gases:$M(SO_2) = 32 + 2 	imes 16 = 64 \ g/mol$$M(CO_2) = 12 + 2 	imes 16 = 44 \ g/mol$$M(PCl_3) = 31 + 3 	imes 35.5 = 137.5 \ g/mol$$M(SO_3) = 32 + 3 	imes 16 = 80 \ g/mol$Comparing the molar masses: $M(PCl_3) > M(SO_3) > M(SO_2) > M(CO_2)$.Since the rate of diffusion is inversely proportional to the square root of the molar mass,the order of the rate of diffusion is: $CO_2 > SO_2 > SO_3 > PCl_3$.

The rate of diffusion of $SO_2$,$CO_2$,$PCl_3$ and $SO_3$ are in the following order:

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