The rate of heat flow through the cross-section of the rod shown in the figure is ($T_2 > T_1$ and the thermal conductivity of the material of the rod is $K$).

  • A
    $\frac{K\pi r_1 r_2 (T_2 - T_1)}{L}$
  • B
    $\frac{K\pi (r_1 + r_2)^2 (T_2 - T_1)}{4L}$
  • C
    $\frac{K\pi (r_1 + r_2)^2 (T_2 - T_1)}{L}$
  • D
    $\frac{K\pi (r_1 + r_2)^2 (T_2 - T_1)}{2L}$

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