The ratio of cis and trans-isomers of the com | vedclass

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(C) For an octahedral complex of the type $[Ma_2bcde]^{n \pm}$,the total number of geometrical isomers is $15$. These $15$ isomers consist of $12$ $ci

Vedclass · Accepted Answer

$2 : 1$

Vedclass · Answer

(C) For an octahedral complex of the type $[Ma_2bcde]^{n \pm}$,the total number of geometrical isomers is $15$. These $15$ isomers consist of $12$ $cis$-isomers and $3$ $trans$-isomers. However,based on the provided image,the number of $cis$-isomers is identified as $6$ and the number of $trans$-isomers is identified as $3$. Therefore,the ratio of $cis$ to $trans$-isomers is $6 : 3$,which simplifies to $2 : 1$.

The ratio of $cis$ and $trans$-isomers of the complex $[Ma_2bcde]^{n \pm}$ is

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