The ratio of mass densities of nuclei of ^{40 | vedclass

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(D) The nuclear mass density is given by the formula $\rho = \frac{M}{V} = \frac{A \cdot m_n}{\frac{4}{3} \pi R^3}$.Since the nuclear radius $R$ is pr

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$1$

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(D) The nuclear mass density is given by the formula $\rho = \frac{M}{V} = \frac{A \cdot m_n}{\frac{4}{3} \pi R^3}$.Since the nuclear radius $R$ is proportional to $A^{1/3}$ (i.e.,$R = R_0 A^{1/3}$),the volume $V$ is proportional to $A$.Therefore,$\rho = \frac{A \cdot m_n}{\frac{4}{3} \pi R_0^3 A} = \frac{m_n}{\frac{4}{3} \pi R_0^3}$.This shows that the nuclear mass density is independent of the mass number $A$.Thus,the mass densities of all nuclei are approximately the same.Consequently,the ratio of the mass densities of $^{40}Ca$ and $^{16}O$ is $1$.

The ratio of mass densities of nuclei of $^{40}Ca$ and $^{16}O$ is close to

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