The ratio of the mean kinetic energy of hydro | vedclass

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Question

(D) The mean kinetic energy $(E)$ of a gas molecule is given by the formula $E = \frac{3}{2} k_B T$,where $k_B$ is the Boltzmann constant and $T$ is t

Vedclass · Accepted Answer

$1:1$

Vedclass · Answer

(D) The mean kinetic energy $(E)$ of a gas molecule is given by the formula $E = \frac{3}{2} k_B T$,where $k_B$ is the Boltzmann constant and $T$ is the absolute temperature.Since the mean kinetic energy depends only on the temperature $(T)$ and not on the nature or mass of the gas molecules,for any two gases at the same temperature,their mean kinetic energies will be equal.Therefore,the ratio of the mean kinetic energy of hydrogen to that of oxygen is $1:1$.

The ratio of the mean kinetic energy of hydrogen and oxygen at a given temperature is

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