The ratio of the nuclear radii of elements wi | vedclass

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(C) The nuclear radius $R$ is given by the formula $R = R_0 A^{1/3}$,where $A$ is the mass number and $R_0$ is a constant.Given mass numbers are $A_1

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$6: 5$

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(C) The nuclear radius $R$ is given by the formula $R = R_0 A^{1/3}$,where $A$ is the mass number and $R_0$ is a constant.Given mass numbers are $A_1 = 216$ and $A_2 = 125$.The ratio of the radii is $\frac{R_1}{R_2} = \frac{R_0 (A_1)^{1/3}}{R_0 (A_2)^{1/3}}$.Substituting the values,$\frac{R_1}{R_2} = \frac{(216)^{1/3}}{(125)^{1/3}}$.Since $216 = 6^3$ and $125 = 5^3$,we have $\frac{R_1}{R_2} = \frac{6}{5}$ or $6:5$.

The ratio of the nuclear radii of elements with mass numbers $216$ and $125$ is

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