The reactance of a circuit is zero. It is pos | vedclass

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(D) The reactance of a circuit is given by $X = X_L - X_C$,where $X_L = \omega L$ is the inductive reactance and $X_C = 1/(\omega C)$ is the capacitiv

Vedclass · Accepted Answer

Both $(A)$ and $(C)$

Vedclass · Answer

(D) The reactance of a circuit is given by $X = X_L - X_C$,where $X_L = \omega L$ is the inductive reactance and $X_C = 1/(\omega C)$ is the capacitive reactance.For the net reactance to be zero $(X = 0)$:$1$. If the circuit contains both an inductor and a capacitor,they must be in resonance such that $X_L = X_C$,which results in $X = 0$.$2$. If the circuit contains only resistors,there are no inductors or capacitors present,so $X_L = 0$ and $X_C = 0$,leading to $X = 0$.Therefore,the circuit can contain both an inductor and a capacitor (in resonance) or neither an inductor nor a capacitor (purely resistive circuit).Thus,the correct option is $(D)$.

The reactance of a circuit is zero. It is possible that the circuit contains:

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