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Question

(A) The reaction sequence involves ozonolysis followed by an intramolecular aldol condensation.$1$. Ozonolysis of $(A)$ with $(i) O_3$ and $(ii) Zn, H

Vedclass · Accepted Answer

$1-$methylcyclohex$-1-$ene

Vedclass · Answer

(A) The reaction sequence involves ozonolysis followed by an intramolecular aldol condensation.$1$. Ozonolysis of $(A)$ with $(i) O_3$ and $(ii) Zn, H_2O$ breaks the double bond to form a dicarbonyl compound $(B)$.$2$. The product shown is a cyclic $\alpha,\beta$-unsaturated ketone ($2$-methylcyclopent$-2-$enone derivative structure).$3$. For the final product to be $2-$methylcyclopent$-2-$enone,the intermediate $(B)$ must be heptane$-2,6-$dione.$4$. This dione is formed by the ozonolysis of $1-$methylcyclohex$-1-$ene. The double bond in $1-$methylcyclohex$-1-$ene is between $C_1$ and $C_2$. Ozonolysis cleaves this bond,resulting in a chain with carbonyl groups at positions $1$ and $6$ relative to the methyl group.

The reactant $(A)$ will be:

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