The reaction $_1H^2 + _1H^3 \to _2He^4 + _0n^1 + \text{energy}$ represents

$_{92}U^{235} + n \to \text{fission product} + \text{neutron} + 3.20 \times 10^{-11} \ J$. The energy released when $1 \ g$ of $_{92}U^{235}$ undergoes fission is

Consider the following nuclear reactions:
$_{92}^{238}M \to _{y}^{x}N + 2_{2}^{4}He$
$_{y}^{x}N \to _{B}^{A}L + 2\beta^{+}$
The number of neutrons in the element $L$ is:

The number of neutrons in the parent nucleus which gives $^{14}N$ on $\beta$-emission is

$_{90}Th^{228}$ emits four alpha and one beta particles. The number of neutrons in the daughter element is:

The hydrogen bomb is based on the phenomenon of: