The reaction of 1-ethylcyclopentene with BH_3 | vedclass

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(D) The reaction of $1-$ethylcyclopentene with $BH_3 / THF$ followed by $H_2O_2 / NaOH$ is a hydroboration-oxidation reaction. This reaction proceeds

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(D) The reaction of $1-$ethylcyclopentene with $BH_3 / THF$ followed by $H_2O_2 / NaOH$ is a hydroboration-oxidation reaction. This reaction proceeds via the syn-addition of $H$ and $OH$ across the double bond. Since the addition is syn,the $H$ atom and the $OH$ group add to the same face of the double bond. This results in the formation of a mixture of enantiomers where the $OH$ group and the ethyl group are in a cis-relationship. Specifically,the product is $2-$ethylcyclopentan-$1-$ol,where the $OH$ and ethyl groups are cis to each other. Looking at the options,the structure representing the cis-isomer is the correct product.

The reaction of $1-$ethylcyclopentene with $BH_3 / THF$ followed by treatment with $H_2O_2 / NaOH$ produces:

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The correct statement about the reaction shown above is:

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