(C) The reaction between $Xe$ and $O_2F_2$ is: $Xe + 2 O_2F_2 \rightarrow XeF_4 + 2 O_2$. Thus,the compound $P$ is $XeF_4$. The complete hydrolysis of

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(C) The reaction between $Xe$ and $O_2F_2$ is: $Xe + 2 O_2F_2 \rightarrow XeF_4 + 2 O_2$. Thus,the compound $P$ is $XeF_4$. The complete hydrolysis of $XeF_4$ proceeds as follows: $XeF_4 + 2 H_2O \rightarrow XeO_2F_2 + 4 HF$. Therefore,the complete hydrolysis of $1 \ mol$ of $XeF_4$ produces $4 \ moles$ of $HF$.