The reaction of 2-methylbuta-1,3-diene with O | vedclass

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(B) Ozonolysis of $2-$methylbuta$-1,3-$diene $(CH_2=C(CH_3)-CH=CH_2)$ involves the cleavage of both double bonds.Reductive ozonolysis using $O_3$ foll

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$CH_3COCHO + HCHO$

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(B) Ozonolysis of $2-$methylbuta$-1,3-$diene $(CH_2=C(CH_3)-CH=CH_2)$ involves the cleavage of both double bonds.Reductive ozonolysis using $O_3$ followed by $Zn-H_2O$ converts the alkene carbons into carbonyl groups (aldehydes or ketones).The reaction proceeds as follows:$CH_2=C(CH_3)-CH=CH_2 \xrightarrow[Zn-H_2O]{O_3} HCHO + CH_3COCHO + HCHO$Thus,the products are $HCHO$ (formaldehyde) and $CH_3COCHO$ (methylglyoxal).Therefore,option $(b)$ is correct.

The reaction of $2-$methylbuta$-1,3-$diene with $O_3$ followed by $Zn-H_2O$ gives:

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