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(B) The reaction of $Zn$ with dilute $HNO_3$ is given by: $4 Zn + 10 HNO_3 (dil.) \longrightarrow 4 Zn(NO_3)_2 + 5 H_2O + N_2O$ Thus,dilute $HNO_3$ pr

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$N_2O$ and $NO_2$

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(B) The reaction of $Zn$ with dilute $HNO_3$ is given by: $4 Zn + 10 HNO_3 (dil.) \longrightarrow 4 Zn(NO_3)_2 + 5 H_2O + N_2O$ Thus,dilute $HNO_3$ produces $N_2O$. The reaction of $Zn$ with concentrated $HNO_3$ is given by: $Zn + 4 HNO_3 (conc.) \longrightarrow Zn(NO_3)_2 + 2 H_2O + 2 NO_2$ Thus,concentrated $HNO_3$ produces $NO_2$. Therefore,the products are $N_2O$ and $NO_2$ respectively.

The reaction of zinc with dilute and concentrated nitric acid,respectively,produces:

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